3x^2+21x-738=0

Solution for 3x^2+21x-738=0 equation:

3x^2+21x-738=0

a = 3; b = 21; c = -738;
Δ = b2-4ac
Δ = 212-4·3·(-738)
Δ = 9297
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9297}=\sqrt{9*1033}=\sqrt{9}*\sqrt{1033}=3\sqrt{1033}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-3\sqrt{1033}}{2*3}=\frac{-21-3\sqrt{1033}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+3\sqrt{1033}}{2*3}=\frac{-21+3\sqrt{1033}}{6}
$